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Q.

The earth's magnetic induction at a certain point is $7 \times 10^{- 5} {Wbm}^{2} .$ This is to be annulled by magnetic induction at the centre of a circular conducting loop of radius 5 cm. The required current in the loop is

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a

0.56 A

b

5.6 A

c

0.28 A

d

2.8 A

answer is B.

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Detailed Solution

$\begin{aligned} \frac{μ_{0}}{4 π} \times \frac{2 π i}{r} = H \Rightarrow \frac{(10^{- 7}) \times 2 \times 3.142 \times i}{0.05} = 7 \times 10^{- 5} \\ ∴ i = \frac{7 \times 0.05 \times 10^{- 5}}{2 \times 3.142 \times 10^{- 7}} = \frac{35}{2 \times 3.142} = 5.6 A \end{aligned}$

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