The earth (mass = 1024 kg) revolves round the Sun with an angular velocity 2×10–7 rad s–1 in a circular orbit of radius 1.5×108 km. Find the force exerted by the Sun on the earth (in 1021 N)

F=mrω2=1024×1.5×108×103×(2×10−7)2=6×1021N

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The earth $(mass = 10^{24} kg)$ revolves round the Sun with an angular velocity $2 \times 10^{- 7} rad s^{- 1}$ in a circular orbit of radius $1.5 \times 10^{8} km$ . Find the force exerted by the Sun on the earth (in $10^{21} N$ )

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answer is 6.

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$F = mr ω^{2}$

$= 10^{24} \times 1.5 \times 10^{8} \times 10^{3} \times {(2 \times 10^{- 7})}^{2}$

$= 6 \times 10^{21} N$

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