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Q.

The earth's radius is about, 6400 km and that of mass is about 3200 km . The mass of the earth is about 10 times the mass of mars. An object weighs 200 N  on the surface of the earth. What is the weight of the object on the surface of mars?


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a

60 N

b

80 N

c

30 N

d

9 N 

answer is B.

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Detailed Solution

The weight of the object on the surface of the mass is 80 N.
Given:
The weight of an object on Mars WM= 200 N
Radius of Earth RE=6400 km
Radius of Mars RM= 3200 km
And the mass of the earth is about 10 times the mass of mars.
At the surface of the earth,
 gE  = GMERE2……(1)
Here, gE= gravitational acceleration, ME=  mass of the earth, RE= radius of the earth and G= universal gravitational constant.
Multiplied by mass 'm' in equation (1) we get,
mgE  = GMEmRE2          WE=GMEmRE2    ….(2)      (∵ w=mg)
Here, WE is the weight of the object on earth.
Similarly, at the surface of mars,
mgM  = GMMmRM2
Where,  gM= gravitational acceleration of mars, MM= mass of the mars, RM= radius of the mars and G= universal gravitational constant.
 WM = GMMmRM2(3)
Here, WM is the weight of the object on the surface of mars.
Now, divide equation (3) by equation (2).
WMWE=mgMmgE=MMME×(RERM)2   WMWE    =110×22                                  WMWE     =410                                                   .
   WMWE      =25  WM=WE×25                 WM=200×25                                 WM= 80 N                       
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