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Q.

The ease with which an alcohol can be halogenated by treating it with HX in the presence of anhydrous  ZnCl2 is 

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a

tertiary alcohol > secondary alcohol < primary alcohol

b

tertiary alcohol < secondary alcohol > primary alcohol

c

tertiary alcohol< secondary alcohol< primary alcohol

d

tertiary alcohol > secondary alcohol > primary alcohol

answer is B.

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Detailed Solution

The decreasing order of reactivity is 3° > 2° > 1 > MeOH.

Thus, B is correct option.

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