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The effective charge experienced by an M( n = 3) electron in an atom of atomic number z is about (z - 7.4) e. The frequency of L X-rays of such an element is

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$\frac{{3cR{{(z - 1)}^2}}}{4}\$

$\frac{{5cR{{(z - 7.4)}^2}}}{{36}}\$

$\frac{{3cR{{(z)}^2}}}{4}\$

$\frac{{5cR{{(z - 7.4)}^2}}}{{18}}\$

answer is D.

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Detailed Solution

$\frac{1}{\lambda } = R{(z - 7.4)^2}\left\{ {\frac{1}{{{2^2}}} - \frac{1}{{{3^2}}}} \right\}\$

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