Q.

The efficiency of a Carnot’s engine at a particular source and sink temperatures is 12 . When the sink  temperature is reduced by 100oC, the engine efficiency becomes 23 .Find the source temperature in Kelvin.

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answer is 600.

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Detailed Solution

1T2T1=12  or  T2T1=12
Further, 1T2100T1=23 or Solving Eqs. Ii) and (ii), we get T1=600K

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