Q.

The electric field and magnetic field components of an electromagnetic wave going through vacuum is described by

Ex=E0sin(kzωt)By=B0sin(kzωt)

Then the correct relation between E0 and B0 is given by

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a

E0×B0=ωk

b

E0=kB0

c

ωE0=kB0

d

kE0=ωB0

answer is A.

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c=E0B0ωK=E0B0Eok=ωB0

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