The electric field at a point on the axis of an electric dipole at a distance r is E1→ and at a distance 2r on the equatorial plane is E2→. If E1=nE2 then n=

E¯1=2KP¯r3&E¯2=−KP¯(2r)3E¯1=−16E¯2

Book Online Demo

Check Your IQ

Try Test

Courses

The electric field at a point on the axis of an electric dipole at a distance r is $\vec{E_{1}}$ and at a distance 2r on the equatorial plane is $\vec{E_{2}}$ . If $E_{1} = n E_{2}$ then n=

see full answer

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

answer is 16.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

${\bar{E}}_{1} = \frac{2 K \bar{P}}{r^{3}} & {\bar{E}}_{2} = \frac{- K \bar{P}}{{(2 r)}^{3}}$

${\bar{E}}_{1} = - 16 {\bar{E}}_{2}$

Watch 3-min video & get full concept clarity