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Q.

The electric field at the centre of a uniformly charged hemispherical shell is E0. Now two portions of the hemisphere are cut from either side and remaining portion is shown in figure. If α=β=π3, then electric field intensity at centre due to remaining portion is

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a

E06

b

E02

c

E03

d

E0

answer is C.

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Detailed Solution

Consider the whole hemisphere as three portion if electric field due to one portion is E1 then
2E1 sin 30 + E1 = E0
2E1=E0
⇒E1=E02

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