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The electric field in a certain region of Earth’s atmosphere is directed vertically down. At an altitude of 300 m the field has magnitude 60.0 N/C; at an altitude of 200 m, the magnitude of field is 100 N/C. The net amount of charge contained in a cube of edge 100 m, with horizontal faces at altitudes of 200 and 300 m is ---- $μ$ C

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answer is 3.54.

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Detailed Solution

$q = \in_{0} \emptyset = \in_{0} A (E_{l} - E_{u}) = 8.85 \times 10^{- 12} \times 100^{2} \times (100 - 60) = 3.54 μC$

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