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The electric field in a region is given by $\vec{E} = (A x + B) \hat{i},$ where E is in $N C^{- 1}$ and $x$ is in metres. The values of constants are A = 20 SI unit and B = 10 SI unit. If the potential at $x = 1$ is $V_{1}$ and that at x = – 3 is $V_{2},$ then $V_{1} - V_{2}$ is:

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320 V

– 48 V

40 V

– 520 V

answer is C.

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Detailed Solution

$V_{1} - V_{2} = - \int_{1}^{- 5} (A x + B) d x = 40 V$

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