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Q.

The electric field in a region is given by : E=(4axyz)i^+2a2zj^+ax2y/zk^ where a is a positive constant. The equation of an equipotential surface will be of the form

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a

z = constant / [x4 y2]

b

None

c

z = constant / [x3y2]

d

z = constant / [xy2

answer is C.

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Detailed Solution

E=(4axyz)i^+2ax2zj^+ax2y/zk^V=Exdx+Eydy+EzdzV=2ax2y2+2ax2yz+2ax2yz+ constant. 3×2ax2yz= constant 6ax2yz= constant z= constant x4y2

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