The electric field in a region of space is given by, E¯=E0i^+2E0j^ where E0=100N/C. The flux of this field through a circular surface of radius 0.02m parallel to the Y-Z plane is nearly:

ds→=π(0.02)2i^=π×4×10−4i^⊥r to yz− plane ;ϕ=E→⋅ds→=100×π×4×10−4=12.56×10−2;=0.125Nm2/c

The electric field in a region of space is given by, E¯=E0i^+2E0j^ where E0=100N/C. The flux of this field through a circular surface of radius 0.02m parallel to the Y-Z plane is nearly:

ds→=π(0.02)2i^=π×4×10−4i^⊥r to yz− plane ;ϕ=E→⋅ds→=100×π×4×10−4=12.56×10−2;=0.125Nm2/c

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The electric field in a region of space is given by, $\bar{E} = E_{0} \hat{i} + 2 E_{0} \hat{j}$ where E₀=100N/C. The flux of this field through a circular surface of radius 0.02m parallel to the Y-Z plane is nearly:

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$3 .14 {Nm}^{2} / C$

$0 .02 {Nm}^{2} / C$

$0 .005 {Nm}^{2} / C$

$0.125 {Nm}^{2} / C$

answer is D.

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Detailed Solution

$\begin{array}{l} \vec{ds} = π (0.02)^{2} \hat{i} = π \times 4 \times 10^{- 4} \hat{i} \\ (⊥^{r} to yz - plane); ϕ = \vec{E} \cdot \vec{ds} = 100 \times π \times 4 \times 10^{- 4} \\ = 12.56 \times 10^{- 2}; = 0.125 {Nm}^{2} / c \end{array}$

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The electric field in a region of space is given by, E¯=E0i^+2E0j^ where E0=100N/C. The flux of this field through a circular surface of radius 0.02m parallel to the Y-Z plane is nearly:

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The electric field in a region of space is given by, $\bar{E} = E_{0} \hat{i} + 2 E_{0} \hat{j}$ where E₀=100N/C. The flux of this field through a circular surface of radius 0.02m parallel to the Y-Z plane is nearly: