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Q.

The electric field in region is given by E=200i^ N/C by x>0 and 200i^ N/C for x<0A closed cylinder of length 2 m and cross-section area 102 m2 is kept in such a way that the axis of cylinder is along x-axis and its center coincides with origin. Find the total charge inside the cylinder  in ×108 C. Take the value of ε0=8.85×1012C2m2N.

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Detailed Solution

Total electric flux coming out of the cylinder is given as ϕ=2ES
ϕ=2×200×102 Vm
Using Gauss's law on the cylindrical surface we have
   qenclosed =ϕε0
qenclosed =4×104×8.85×1012=35.4×108 C

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