The electric field intensity at a point situated 4 meters from a point charge is 200 N/C. If the distance is reduced to 2 meters, the field intensity will be

The electric field intensity is given by

Here, Q is the point charge k is the proportionality constant and d is the distance between the charges.

Now E at a point  situated 4 m from a point charge,

Similarly, if the distance is reduced to  2 m, then

Therefore,

Substitute the given values, we get

.

Thus, the field intensity will be 800 N/C.