The electric field intensity produced by the radiation coming from a 100W bulb at a distance of 3m is E. The electric field intensity produced by the radiation coming from 60W at the same distance is $\sqrt{\frac{x}{5}} E,$ where the value of x= _______.

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answer is 3.

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Detailed Solution

$c ε_{0} E^{2} = \frac{100}{4 π \times 3^{2}} c ε_{0} {(\sqrt{\frac{x}{5}} E)}^{2} = \frac{60}{4 π \times 3^{2}} \frac{x}{5} = \frac{3}{5} \Rightarrow x = 3$

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