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The electric field on two sides of a large charged plate is shown in the below Fig. The charge density on the plate in S.I. units is given by ( $ε_{0}$ is the permittivity of free in S.I. units)

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$4 ε_{0}$

zero

$2 ε_{0}$

$10 ε_{0}$

answer is B.

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Detailed Solution

$Considering an small area A Flux through this area is given by (E_{2} - E_{1}) A = \frac{Aσ}{ε_{0}} \Rightarrow (12 - 8) = \frac{σ}{ε_{0}} \Rightarrow σ = 4 ε_{0}$

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