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Q.

The electric field strength at the center of uniformly charged ring is _____. (Q=charge on the ring, r=distance from center of ring, R= radius of ring)

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a

14πε0Qr2

b

14πε0QrR2+r2

c

0

d

None

answer is C.

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Detailed Solution

detailed_solution_thumbnail

The electric field due to the ring at its axis at a distance of r is given as

E=kqrr2+R232

Put x=0,

⇒E=0

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