The electric flux is $ϕ = ασ + βλ$ where $λ$ and $σ$ are linear and surface charge density, respectively, $(\frac{α}{β})$ represents

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charge

electric field

area

displacement

answer is C.

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Detailed Solution

$\begin{array}{l} ϕ = ασ + βλ \\ [ϕ] = [ασ] = [βλ] \\ [α] = \frac{[ϕ]}{[σ]} \\ [β] = \frac{[ϕ]}{[λ]} \\ [\frac{α}{β}] = \frac{[λ]}{[σ]} \\ = \frac{[Q / L]}{[Q / Area]} = [\frac{Area}{Length}] \\ [\frac{α}{β}] = L \end{array}$

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