The electric flux through a Gaussian surface that encloses three charges given by ${\mathrm{q}}_1=-14$  nC, ${\mathrm{q}}_2=78.85$ nC, ${\mathrm{q}}_3=-56$ nC

Given Data: ${\mathrm{q}}_1=-14\mathrm{nc},{\mathrm{q}}_2=78.85\mathrm{nC},{\mathrm{q}}_3=-56\mathrm{nC}$ are three charges enclosed in a gaussain surface.

Formula Used: $\varphi =\frac{Q_{\text{enclosed }}}{{\epsilon }_0}$

Detailed Solution:

By Gauss law,

flux $\varphi =\frac{Q_{\text{enclosed }}}{{\epsilon }_0}$

$\varphi =\frac{-14nC+78nC-56nC}{{\epsilon }_0}$

$=\frac{8.85\times {10}^{-9}C}{8.85\times {10}^{-12}}={10}^3$