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The electric intensity due to a dipole of length 10 cm and having a charge of 500 μC , at a point on the axis at a distance 20 cm from one of the charges in air, is

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a
6.25×107N/C
b
9.28×107N/C
c
13.1×1111N/C
d
20.5×107N/C

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detailed solution

Correct option is A

Ep=EqEq=14πϵ0q20×1022q30×1022=14πϵ0q20×1022q30×1022=9×109×500×106×102141945×107×536=6.25×107

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