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Q.

The electric potential V at any point (x, y, z) in space is given by V = 4x2 volt where x, y and z are all in metre. The electric field at the point (1 m, 0, 2 m) in vm-1 is

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a

8 along positive x-axis

b

16 along positive :X-axis

c

8 along negative x-axis

d

16 along negative x-axis

answer is A.

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Detailed Solution

E=-Vr=-d4x2dx=-8x . Hence E at a point whose x-coordinate is x= 1 m is

  E= -8xi^  =-8i^ Vm-1

The negative sign shows that E is along the negative x-axis.

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