Q.

The electric potential V at any point (x,y,z) in space is given by equation V=4x2 volt where x, y and z are all in metre. The electric field at the point (1m,0,2m) in V/m is:

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a

8 along positive x-axis

b

8 along negative x-axis

c

16 along positive x-axis

d

16 along negative x-axis

answer is A.

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Detailed Solution

E=i^Vx+j^Vy+k^Vz

Given V=4x2

E=i^(8x) [Magnitude of E is 8V/m]

Hence, electric field is 8V/m along negative x-axis

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