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Q.

The electric potentials at the two ends of a conductor are 10 V and 5 V, respectively. 5 J of work needs to be done to move a certain amount of charge from the end at a higher potential to the end at a lower potential. Find the amount of charge moved.

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a

1.0 coulomb

b

1.5 coulomb

c

1.2 coulomb

d

0.1 coulomb

answer is B.

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Detailed Solution

The potential difference between the two ends of the conductor (V) = 10 V − 5 V = 5V.

Work done (W) = 5 J Charge (Q) =?

Potential difference = work charge

V = W/Q

⇒ Q = W/V = 5J/5V = 1 coulomb

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