The electrical resistance of a column of 0.04M NaOH solution of diameter 1.2 cm and length 50 cm is $5.55\times {10}^3$ ohm, the resistivity of the column would be

Here required formula is $\mathrm{R}=\mathrm{\rho }\frac{\mathrm{l}}{\mathrm{\alpha }}$

For that given is:

d=1.2 cm i.e. $\mathrm{r}=\frac{1.2}{2}=0.6 \mathrm{cm}$      

Length = 50 cm ,      $\mathrm{R}=5.55\times {10}^{3 }$ohm

Now, we have to calculate $\mathrm{\alpha }$

$$\begin{gathered} \mathrm{area}={\mathrm{\pi r}}^{2 }=3.14\times {(0.6)}^2 =1.13 {\mathrm{cm}}^2 \\ \mathrm{area} =1.13 {\mathrm{cm}}^2 \end{gathered}$$

We have to find out resistivity $\mathrm{\rho }=?$

Now, by putting all above values in formula we get

$$\begin{gathered} \mathrm{R}=\mathrm{\rho }\frac{\mathrm{l}}{\mathrm{a}} \\ \mathrm{\rho }=\frac{\mathrm{R}\times \mathrm{a}}{\mathrm{l}}=\frac{5.55\times {10}^3\mathrm{ohm}\times 1.13 {\mathrm{cm}}^2}{50 \mathrm{cm}} \\ \mathrm{\rho }=1.2543\times {10}^2\mathrm{ohm} \mathrm{cm} \\ \mathrm{\rho }=125.43 \mathrm{ohm} \mathrm{cm} \end{gathered}$$

Therefore option A is correct.