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Q.

The electricity required in coulombs for the oxidation of 0.1 mol of FeO to Fe2O3 is

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a

96.5 C

b

96500 C

c

2 x 96500 C

d

9650 C

answer is C.

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Detailed Solution

H2O+2FeOFe2O3+2H++2e

For 2 moles → 2 × 96500 coulombs
So for 0.1 mol → 9650 coulombs

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