The electrochemical cell :

${\text{Zn}}_{\left(\text{s}\right)}/{\text{ZnSO}}_{\text{4}}\left(\text{0.01M}\right)\parallel {\text{CuSO}}_{\text{4}}\left(\text{1M}\right)/{\text{Cu}}_{\left(\text{s}\right)}$.

The emf of this cell is  ${\text{E}}_{\text{1}}$ when the concentration of ${\text{ZnSO}}_4$ is changed to 1.0M and that of  ${\text{CuSO}}_{\text{4}}$  changed to 0.01M, the emf changes to ${\text{E}}_2$. The relationship between  ${\text{E}}_{\text{1}}$and  ${\text{E}}_2$ is  $\left(\text{Given\hspace{0.17em}}\frac{\text{RT}}{\text{F}}=0.059\right)$