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Q.

The electron gain enthalpy of chlorine is 3.7eV. How much energy in Kcal is released when 2g of chlorine atoms is completely converted to Cl^– ions in the gaseous state? (1eV = 23.06 Kcal)

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a

4.8 Kcal

b

4 Kcal

c

3.6 Kcal

answer is C.

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Detailed Solution

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$Cl + e^{-} \to {Cl}^{-} + 3.7 ev$

Energy released for 1 mol (or 35.5g) =3.7×23.06 kcal/mol

$∴$ Energy released for conversion of 2g gaseous chlorine into Cl⁻ ions

$= \frac{3.7 \times 23.06}{35.5} \times 2 = 4.8 Kcal .$

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