The electronegativity difference between N and F is greater than then between N and H yet the dipole moment of $N H_{3} (1.5 D)$ is larger than that of $N F_{3} (0.2 D)$ . This is because

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in $N H_{3}$ as well as $N F_{3}$ , the atomic dipole and bond dipole are in opposite directions

in $N H_{3}$ as well as in $N F_{3}$ , the atomic dipole and bond dipole are in the same direction

in $N H_{3}$ the atomic dipole and bond dipole are in the opposite directions whereas in $N F_{3}$ , these are in the same direction

in $N H_{3}$ the atomic dipole and bond dipole are in the same direction whereas in $N F_{3}$ these are in opposite directions

answer is A.

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Detailed Solution

In $N H_{3}$ the atomic dipole ( orbital dipole due to lone pair) and bond dipole are in the same direction whereas in $N F_{3}$ , these are in opposite direction so, in the former case, they are added up whereas in the latter case, net result is reduction of dipole moment. It has been shown in the following figure:
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