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Q.

The electronic configuration 1s2 2s2 2p6 3s1 3p3 3d2 represents

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a

Ground state

b

1st excited state

c

2nd excited state

d

3rd excited state

answer is C.

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Detailed Solution

since total no. of electrons here are 16 and original configuration(ground state) should be 1s2 2s2 2p6 3s2 3p4 3d0

So 1 electron each from 3s and 3p go into 3d in 2nd excited state.

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