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Q.

The electronic configuration of Beryllium is

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a

$[H e] 2 s^{2}$

b

$[N e] 3 s^{2} 3 p^{3}$

c

$[N e] 3 s^{2} 3 p^{2}$

d

$[N e] 3 s^{2} 3 p^{1}$

answer is B.

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Detailed Solution

Be – 4 - $1 s^{2} 2 s^{2}$

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