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Q.

The electronic configuration of bivalent europium and trivalent cerium are
[atomic no. Xe = 54, Ce = 58, Eu = 63]

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a

$[Xe] 4 f^{7} and [Xe] 4 f^{1}$

b

$[Xe] 4 f^{2} and [Xe] 4 f^{7}$

c

$[Xe] 4 f^{4} and [Xe] 4 f^{9}$

d

$[Xe] 4 f^{7} 6 s^{2} and [Xe] 4 f^{2} 6 s^{2}$

answer is D.

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Detailed Solution

The electronic configuration of ${Eu}^{+ 2} = [Xe] 4 f^{7}$ and ${Ce}^{+ 3} = [Xe] 4 f^{1}$ .

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