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Q.

The electronic configuration of chromium $(z = 24)$ is

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a

2,8, 14

b

2, 8, 8, 6

c

2, 8, 13, 1

d

2,8, 12,2

answer is D.

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Detailed Solution

$Cr = 24 = \frac{1 s^{2}}{2}, \frac{2 s^{2}, 2 p^{6}}{8}, \frac{3 s^{2} \cdot 3 p^{6}}{8}, \frac{4 s^{1}}{1}, 3 d^{5} .$

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