The electronic configuration of four elements are :

$$\begin{gathered} \left(\mathrm{P}\right)\left[\mathrm{Xe}\right]6{\mathrm{s}}^2 \\ \left(\mathrm{Q}\right)\left[\mathrm{Xe}\right]4{\mathrm{f}}^{14},5{\mathrm{d}}^1,6{\mathrm{s}}^2 \\ \left(\mathrm{R}\right)\left[\mathrm{Ar}\right]4{\mathrm{s}}^2,4{\mathrm{p}}^5 \\ \left(\mathrm{S}\right)\left[\mathrm{Ar}\right]3{\mathrm{d}}^{10},4{\mathrm{s}}^2,4{\mathrm{p}}^3 \end{gathered}$$

Which of the following is/are correct?

P$\to$ $s$-block element, 

Q$\to$ $f$-block element,

R$\to$ halogen,

 $S$$\to$ shows maximum covalency of 5

Thus correct statement is "(R) has highest electron affinity among given elements".