The electronic configuration of four elements L,P, Q, and R are given in brackets
$L (1 s^{2}, 2 s^{2} 2 p^{4}); Q (1 s^{2}, 2 s^{2} 2 p^{6}, 3 s^{2} 3 p^{5})$
$P (1 s^{2}, 2 s^{2} 2 p^{6}, 3 s^{1}); R (1 s^{2}, 2 s^{2} 2 p^{6}, 3 s^{2})$
The formulae of ionic compounds that can be formed between these elements are

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

$L_{2} P, RL, PQ$ and $R_{2} Q$

$L P, R L, P Q$ and $R_{2} Q$

$P_{2} L, RL, PQ$ and

$LP, R_{2} L, P_{2} Q$ and $RQ$

answer is C.

(Unlock A.I Detailed Solution for FREE)

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

According to the given electronic configurations, valency of L is -2, Q is -1, P is +1, and R is +2.

The first compound forms is PQ, where P transfers one electron to Q and forms an ionic compound.
The second compound forms is P₂L, where each P transfers one electron to L and forms an ionic compound.
The third compound forms is RL, where one R transfers its 2 electrons to L and forms an ionic compound.
The fourth compound is RQ₂, where each Q accepts one electron from R and forms an ionic compound.

So, the compounds form from L,P, Q, and R are $P_{2} L, RL, PQ$ and ${RQ}_{2} .$ .

Watch 3-min video & get full concept clarity