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The electronic configuration of Pt (atomic number 78 ) is :

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$[Xe] 4 f^{14} 5 d^{9} 6 s^{1}$

$[Kr] 4 f^{14} 5 d^{10}$

$[Xe] 4 f^{14} 5 d^{10}$

$[Xe] 4 f^{14} 5 d^{8} 6 s^{2}$

answer is A.

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Detailed Solution

₇₈Pt = [Xe] 4f¹⁴ 5d⁹ 6s¹ (Exceptional electronic configuration)

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