Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

The electrons identified by quantum numbers n and l (i) n = 4, l = 1 (ii) n = 4, l = 0 (iii) n =3, l = 2 (iv) n = 3, l = 1 can be placed in order of increasing energy, from lowest to highest as

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

(i) < (iii) < (ii) < (iv)

b

(iii) < (i) < (iv) < (ii)

c

(iv) < (ii) < (iii) < (i)

d

(ii) < (iv) < (i) < (iii)

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

detailed_solution_thumbnail

The greater is the value of (n+l), the greater is the energy of orbitals.

(i) n=4,l=1⇒ 4p orbital

(ii) n=4,l=0⇒ 4s orbital

(iii) n=3,l=2⇒ 3d orbital

(iv) n=3,l=1⇒3p orbital

According to the Aufbau principle, energies of above-mentioned orbitals are in the order of-

The increasing order of energy (iv)3p < (ii)4s < (iii)3d < (i)4p

Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring