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The element having greatest difference between its first and second ionization energies, is

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answer is D.

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Detailed Solution

$K = 2, 8, 8, 1$

After removal of one $\bar{e}$ the second $\bar{e}$ we have to remove from another shell which has an octet configuration, hence there is a large difference between 1^st and 2^nd I.E

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