The elements ‘A’ and ‘B’ combine together to give two compounds B2A3 and B2A. The weight of 0.05 moles of B2A3 is 9 gm and the weight of 0.1 mole of B2A is 10 gm. The atomic weights of A and B are respectively

(2b + 3a) × 0.05 = 9(2b + a) × 0.1 =10 ⇒a = 40, b = 30

The elements ‘A’ and ‘B’ combine together to give two compounds B2A3 and B2A. The weight of 0.05 moles of B2A3 is 9 gm and the weight of 0.1 mole of B2A is 10 gm. The atomic weights of A and B are respectively

(2b + 3a) × 0.05 = 9(2b + a) × 0.1 =10 ⇒a = 40, b = 30

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The elements ‘A’ and ‘B’ combine together to give two compounds B₂A₃ and B₂A. The weight of 0.05 moles of B₂A₃ is 9 gm and the weight of 0.1 mole of B₂A is 10 gm. The atomic weights of A and B are respectively

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30, 40

50, 50

80, 20

40, 30

answer is D.

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(2b + 3a) × 0.05 = 9
(2b + a) × 0.1 =10 $\Rightarrow$ a = 40, b = 30

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The elements ‘A’ and ‘B’ combine together to give two compounds B2A3 and B2A. The weight of 0.05 moles of B2A3 is 9 gm and the weight of 0.1 mole of B2A is 10 gm. The atomic weights of A and B are respectively

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The elements ‘A’ and ‘B’ combine together to give two compounds B₂A₃ and B₂A. The weight of 0.05 moles of B₂A₃ is 9 gm and the weight of 0.1 mole of B₂A is 10 gm. The atomic weights of A and B are respectively