The elevation in boiling point for 1 molal solution of non-volatile solute A is 6K. The depression in freezing point for 0.5 molal solution of AB in the same solvent is 3K. The ratio of K_b and K_f i.e., K_b/K_f is 3 : 2. The percentage dissociation of AB in the solution is

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Detailed Solution

$\frac{∆ T_{b}}{∆ T_{f}} = \frac{i K_{b} m_{1}}{i K_{f} m_{2}}$

$\frac{6}{3} = \frac{1 \times K_{b} \times 1}{[1 + α (2 - 1)] K_{f} \times 0.5}$

$\frac{6}{3} = \frac{1 \times 3 \times 1}{[1 + α (2 - 1)] \times 2 \times 0.5}$

$1 + α = 1.5$

$% α = 50 %$

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