Q.

The elevation in boiling point of an aqueous solution of Nacl is 0.01C.if its van’t Hoff factor is 1.92, the molality of Nacl solution is (Kb for water=0.52 K kg mol1)

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a

0.02m

b

0.001m

c

0.005m

d

0.01m

answer is A.

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Detailed Solution

Give ΔTb=0.01C=0.01K,i=1.92

Kb=0.52Kkgmol1

As we know that,

ΔTb=iKb×m

m=0.011.92×0.52mol/kg

 M(molality) = 0.01mol/kg or 0.01 m

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