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Q.

The elongation of a spring of length ‘L’ and of negligible mass due to a force is $' x'$ . The spring is cut into two pieces of length in the ratio $1 : n$ . The ratio of the respective spring constants is

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a

n : 1

b

1 : n

c

n^{2} : 1

d

1 : n^{2}

answer is A.

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Detailed Solution

K \propto \frac{1}{l}

$\frac{K_{1}}{K_{2}} = \frac{l_{2}}{l_{1}} = \frac{n}{1}$

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