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The elongation of a wire is ‘e’ when it is elongated by certain force. If the wire melted and made into another wire of double cross-sectional area, then its elongation for the same force is

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e 2

e 4

answer is D.

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Detailed Solution

$e = \frac{FL}{AY} = \frac{FV}{A^{2} Y}$

$e α 1 A 2 (v o l u m e c o n s tan t) e 2 = e 4$

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