em=1.6×10−191.67×10−24=9.57×104c/g

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The e/m of proton is

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1.78 × 10⁸ c/g

9.57 × 10⁴ c/g

19.14 × 10⁴ c/g

0.478 × 10⁴ c/g

answer is B.

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Detailed Solution

$\frac{e}{m} = \frac{1 .6 \times 10^{- 19}}{1 .67 \times 10^{- 24}} = 9 .57 \times 10^{4} c / g$

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