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The emf and internal resistance of the battery shown in figure are 4.3 V and $1 Ω$ respectively. The external resistance R is $50 Ω$ . The resistance of the voltmeter and ammeter are $200 Ω$ and $2 Ω$ respectively. Find the readings of the two meters.

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0.4 A, 1 V

0.1 A, 2 V

0.1 A, 4 V

04.A, 4 V

answer is B.

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Detailed Solution

First of all the draw the equivalent circuit diagram, current flowing through circuit $= \frac{4.3}{(50 | | 200 + 2 + 1)} = 0.1 A$

Voltmeter reading = 4.3 – 0.1 x 3 = 4 V

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