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The EMF of a cell formed by combining a particular electrode with standard calomel electrode is found to be 0.344 V and calomel electrode is found to act as cathode. If the same electrode is combined with standard hydrogen electrode, the EMF of the cell will be (Given standard reduction potential, ${E^{0}}_{Calomel} = + 0.244 V$ )

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0.344V

0.244V

0.588V

0.100V

answer is D.

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Detailed Solution

E_{cell}^o = E_{cathode}^o - E_{anode}^o

calomel is Cathode.

If the same electrode is connected to NHE then NHE acts as cathode and other electrode acts as anode because SRP of NHE is greater than other electrode.

E_{cell}^o = E_{cathode}^o - E_{anode}^o = 0 - left( { - 0.1} right) = 0.1V

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