The emf of a cell formed by dipping two electrodes of metal (M) in two solution of its salt in which the concentration of metal ion (Mn+) is 0.1 M and 0.001 M was observed to be 0.03 volt at 25°C. What is the valency of the metal ion if the two half cells are connected using salt bridge?[Given 2.303RTF=0.06]

0.03=0.060nlog⁡0.10.001⇒n=4

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The emf of a cell formed by dipping two electrodes of metal (M) in two solution of its salt in which the concentration of metal ion (Mⁿ⁺) is 0.1 M and 0.001 M was observed to be 0.03 volt at 25°C. What is the valency of the metal ion if the two half cells are connected using salt bridge?
[Given $2.303 \frac{RT}{F} = 0.06$ ]

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answer is 4.

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$0.03 = \frac{0.060}{n} \log [\frac{0.1}{0.001}] \Rightarrow n = 4$

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