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Q.

The EMF of the following cells are 

CuCu2+(1M)Ag+(1M)Ag,E0=0.46VZnZn2+(1M)Cu2+(1M)Cu,Eo=1.10V
The EMF of the cell 

ZnZn2+(1M)Ag+(1M)Ag will be 

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a

1.56 V

b

0.64 V

c

– 1.56V

d

2.02V

answer is A.

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Detailed Solution

Cu+2Ag+2Ag+Cu+2         E10=0.46V
Zn+Cu2+ Zn2++Cu            E2o = 1.10 V 
Zn+2Ag+Zn2++2Ag          E3o
G3o = G1o+G2o
nFE3o = nFE1o+nFE2o  n is 2 in all
Hence 
E3o = 0.46V+1.10 V = 1.56 V

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