The EMF of the following galvanic cell isZn/Zn(0.1M)+2//Cu(0.1M)+2/CuE∘Cu+2/Cu=0.34V, E∘Zn+2/Zn=−0.76V

Net reaction isZn+Cu+2⇌Cu+Zn0.1M+2EMF=Ecell 0−0.06nlog⁡CPCR=1.1−0.062log⁡0.10.1

The EMF of the following galvanic cell isZn/Zn(0.1M)+2//Cu(0.1M)+2/CuE∘Cu+2/Cu=0.34V, E∘Zn+2/Zn=−0.76V

Net reaction isZn+Cu+2⇌Cu+Zn0.1M+2EMF=Ecell 0−0.06nlog⁡CPCR=1.1−0.062log⁡0.10.1

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The EMF of the following galvanic cell is
$Z n / Z n_{(0.1 M)}^{+ 2} / / C u_{(0.1 M)}^{+ 2} / C u$
$[E^{\circ} {Cu}^{+ 2} / Cu = 0.34 V, E^{\circ} {Zn}^{+ 2} / Zn = - 0.76 V]$

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1.06 V

1.2 V

1.0 V

1.1 V

answer is A.

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Detailed Solution

Net reaction is

$Zn + {Cu}^{+ 2} ⇌ Cu + {Zn}_{0.1 M}^{+ 2}$

$EMF = E_{cell}^{0} - \frac{0.06}{n} \log \frac{C_{P}}{C_{R}}$

$= 1.1 - \frac{0.06}{2} \log \frac{0.1}{0.1}$

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The EMF of the following galvanic cell isZn/Zn(0.1M)+2//Cu(0.1M)+2/CuE∘Cu+2/Cu=0.34V, E∘Zn+2/Zn=−0.76V

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The EMF of the following galvanic cell is
$Z n / Z n_{(0.1 M)}^{+ 2} / / C u_{(0.1 M)}^{+ 2} / C u$
$[E^{\circ} {Cu}^{+ 2} / Cu = 0.34 V, E^{\circ} {Zn}^{+ 2} / Zn = - 0.76 V]$