The emissivity of a perfect black body is increased to 16 times by increasing its temperature. If the initial temperature is T, then final temperature of that black body is

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8 T

2 T

4 T

16 T

answer is C.

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Detailed Solution

$\begin{array}{l} Q \propto T_{1}^{4} and 16 Q \propto T_{2}^{4} \\ or 16 = (T_{2}^{4} / T_{1}^{4}) or 2^{4} = {(T_{2} / T_{1})}^{4} \\ ∴ T_{2} = 2 T \end{array}$

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